107 g of a ammonium chloride sample decomposes on heating to give HCl(g) and 25.5 g of NH3(g). The percentage purity of ammonium chloride sample is

NH4Cl(s)⟶ΔNH3(g)+HCl(g) 53.5 g          17 g         36.5 g 17 g NH3 is obtained by 53.5 g NH4ClSo, 25.5 g NH3 will be obtained by=53.517×25.50=80.25 g NH4Cl∴ % purity of sample =80.25107×100=75%