2.1 g of anhydrous barium chloride solution was treated with excess of dil. H2SO4. The weight of BaSO4 ppt. after filtration, washing and drying was found to be 2.36 g. Calculate the equivalent weight of barium.

Wt. of BaCl2=2.1g; wt. of BaSO4=2.36gEq. wt. of Ba=E; Eq. wt. of Cl−radical = Formula wt. of Cl−radical  Valency of Cl−=35.5/1=35.5;  Eq. wt. of SO42−= Formula wt. of SO42− radical  Valency of SO42−=[32+(4×16)]/2=48. We know that :  wt. of BaCl2 wt. of BaSO4=Eq⋅ wt. of BaCl2Eq⋅ wt. of BaSO4;2.1g2.36g=E+ eq. wt. of Cl−E+ eq. wt. of SO42− or 2.1g2.36g=E+35.5E+48;2.1E+48(2.1)=2.36E+35.5(2.36);2.1E+100.8=2.36E+83.780.26E=17.02;E=17.02/0.26=65.46 Ans.