A(g) + 3B(g) ⇌ 4C(g) . Initial concentration of A is equal to that of B. The equilibrium concentration of A and C are equal. KC is equal to

Let initial concentration of A and B is 1 M each. At equillibrium [A] reacted = x M and [B] reacted = 3xAt equillibrium [A] = 1 -x ; [B] = 1-3x ; [C] = 4xGiven that at equillibrium [A] = [C]1-x = 4x⇒x =0.2[A] = 1-0.2=0.8[B] = 1-3x = 1-0.6 =0.4[C] = 4x =0.8Kc = C4AB3=0.840.80.43= 8