20 g of a binary electrolyte (mol. wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is −0.74oC,Kf=1.86 K molality−1. The degree of ionization of the electrolyte is

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answer is D.

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Detailed Solution

ΔT=1000×Kf×wm×w∴ 0.74=1000×1.86×20m×500∴ m=100Now, normal, mol. wt.exp. mol. wt.=1+α(n-1)(Where n =2 due to binary electrolyte)∴ 100100=1+α ∴ α=0

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