20g of a binary electrolyte (molecular weight = 100) are dissolved in 500g of water. The freezing point of the solution is −0.744∘ C; Kf=1.86 K molality−1. The degree of dissociation of electrolyte is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
50%
b
75%
c
100%
d
zero
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Applying Depression freezing point,ΔTf=iKf×m Where, ΔTf is the Depression freezing point Kf is m is the molality the Cryoscopic constant i is the Van’t Hoff factor⇒0.744=i×1.86×20100×1000500⇒i=5×0.7441.80×2=1∴α=1−in−1=1−12−1=01=0
20g of a binary electrolyte (molecular weight = 100) are dissolved in 500g of water. The freezing point of the solution is −0.744∘ C; Kf=1.86 K molality−1. The degree of dissociation of electrolyte is