60g CH3COOH & 23g C2H5OH are mixed & heated until equilibrium is reached. If 4.5g H2O is present at equilibrium, total number of moles at equilibrium is

CH3COOH  +  C2H5OH  ⇌  CH3COOC2H5+H2O         1                          12                        0                    0    (1−x)               (12−x)                   x                    x Given that    x=4.518=14 Total moles of equilibrium =1  −  x  +12  −  x  +  2x                                                 =32