11.0 g of CO2 gas are introduced in a vessel of 4L capacity at 37°C. Calculate the pressure of the gas in bar in the container.

wt. of CO2=11.0g;mol. wt. of CO2=12+(2×16)=44gmol−∴ no. of mol of CO2=wt.mol.wt=11.044gmol−=0.25molP=?,T=37+273=310K,V=4L=4×10−3m3R=8.314Pam3K−mol−.We know that: P=nRT;P=nRTV=0.25mol×8.314Pam3K−mol−×310K4×10−3m3or P=161083Pa=161083Pa×1bar105Pa                                  = 1.61 bar