Q.
10 g of CaCO3 contains
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a
10 moles of CaCO3
b
0.1 g atom of Ca
c
6 x 1023 atoms of Ca
d
0.1 of equivalent of Ca
answer is B.
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Detailed Solution
Mw2 of CaCO3=40+12+48=100Moles of CaCO3 in = 10 g = 10100 =0.1 mol = 0.1g atom
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