6 g of a compound exerts the same osmotic pressure as that of 0.05 M glucose solution. Find out the molecular formula of the compound if empirical formula of non-electrolyte is CH2O.

Osmotic pressure ∝ concentration∴ Concentration of the compound = Concentration of the glucose       6M=0.05 M=120Empirical formula (CH2O) mass = 12+ 2+ 16 = 30 g mol-1          n=molecular massempirical formula mass    =12036=4Molecular formula =CH2On=CH2O4=C4H8O4