Ge(II) compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It can be due to
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a
Pb is more electropositive thanGe
b
Ionization potential of lead is less than that of Ge
c
Ionic radii of Pb2+ andPb4+ are larger than thoseGe2+ and Ge4+
d
More pronounced inert pair effect in lead than in Ge
answer is D.
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Detailed Solution
Ge(II) tends to acquireGe(IV) state by loss of electrons. Hence it is reducing in nature . Pb(IV) tends to acquire Pb(II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.