25 g ethylene glycol is present in 100 g of water. The solution is cooled to–10°C. Kf for H2O is 1.86 K kg mol–1. The amount of ice separated on cooling is

∆Tf=Kf×wm×1000WIn gms10=1.86×2562×1000WWweight of solvent= 75 grwglycol remains constant on cooling; only water freezes  Therefore, Ice separated   =WH2o initial taken-WH2Oremaining =100-75=25 gm