First slide

Gibb's free energy , Cell potential, Equilibrium constant

Question

G⁰ of graphite and diamond respectively are zero and 2.9 kJ/mole. Gibbs energy change for producing 24g diamond from graphite in kilo joules is

Moderate

Solution

Graphite $\rightarrow$ Diamond
$\begin{array}{l} \Delta G = G_{diamond}^0 - G_{graphite}^0\\ \,\,\,\,\,\,\,\,\, = 2.9 - 0 = 2.9KJ/mole \end{array}$
For 12gm ,    ΔG = 2.9KJ
       24gm      ΔG = ?
                      $= 2.9\times \frac{24}{12}=5.8KJ$

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