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Q.

0.078 g of hydrocarbon occupies 22.4 ml of volume at , 1 atm and 0"C. The empirical formula of the hydrocarbon is CH. The molecular formula is:

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a

C2H2

b

C4H4

c

C6H6

d

C8H8

answer is C.

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Detailed Solution

22.4 mL of hydrocarbon weighs 0.078 gThen, 22400mL of hydrocarbon weigh=0.07822.4×22400g=78g= molar mass Emprical mass : at. mass of C + at. mass of H = 12 + I = 13 gn=7813=6∴ M.F =( E.F )n=(CH)6 or C6H6

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0.078 g of hydrocarbon occupies 22.4 ml of volume at , 1 atm and 0"C. The empirical formula of the hydrocarbon is CH. The molecular formula is: