1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

Metal hydroxide →ignition Metal oxideEquate the number of equivalents  of compounds in the reactionwt.Emetal hydroxide= wt.Emetal oxide Emetal hydroxide = EM+EOH- Emetal oxide = EM+EO-2wt. of  metal  hydroxidewt.  of  metal  oxide=EM+EOH−EM+EO−2⇒    1.5200.995 =  x+17x+8⇒   1.520x+1.520 ×  8=0.995x+0.995×171.520x+12.160=0.995x+16.915or   0.525x=4.755x=4.7550.525=9