1 g of I2 is in 10 mL CHCI3. When 400 mL H2O is added into it, concentration of I2 in CHCI3 falls to 0.80 g. Hence, partition coefficient of I2 in CHCI3 and H2O is

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400

200

300

160

answer is D.

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Detailed Solution

I2 present in 10mLCHCl3=0.8g I2 extracted into 400mLH2O=0.2g∴ CI2CHCl3=0.810gmL−1CT2H2O=0.2400gmL−1∴ CI2CHCl3CI2H2O=0.8100.2400=160

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