1,.947 g of iodine I2 (I = 127) was allowed to react with 1.056 g of Sn (119) to form SnxIy, along with 0.601 g of unreacted Sn. Thus, SnxIy, is

Sn taken = 1.056 gSn unreacted = 0.601 gSn used = 1.056 - 0.601 = 0.455 g Mole                                                         RatioSn           0.455 / 119 = 3.82 × 10-3             1.0iodine     1.947 / 127 = 1.53 x 10-2              4.0Thus, compound is SnI4