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Q.

4.9 g of K2Cr2O7 is taken to prepare 0.1 L of the solution 10 mL of this solution is further taken to oxidize Sn2+ ion into Sn4+ ion Sn4+ so produced is used in second reaction to prepare Fe3+ ion then the millimoles of Fe3+ ion formed will be (assume all other components are in sufficient amount) [Molar mass of K2Cr2O7 = 294 g].

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a

5

b

20

c

10

d

none of these

answer is C.

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Detailed Solution

K2Cr2O7 + Sn2+ →  Sn4+ + Cr3+Sn4+ + Fe2+→ Fe3+Meq. of Sn4+ = Meq of  K2Cr2O7Meq. of Sn4+ = Meq of Fe3+Meq. of Fe3+ = meq of K2Cr2O7NK2Cr2O7 = 4.9 × 6294 × 0.1 = 1Meq. of Fe+3 =(NV) of K2Cr2O7millimol x n-factor = 1 x 10millimol = 10
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