20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample? (At.wt.of Mg=24 )

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 3.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

MgCO3(s)84 g⟶ΔMgO(s)40 g+CO2(g) 84 g of MgCO3≡40 g of MgO∴ 20 g of MgCO3≡4084×20=9.52 g of MgO Actual yield =8 g of MgO∴ % purity =89.52×100=84%

Watch 3-min video & get full concept clarity