20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample? (At.wt.of Mg=24 )

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answer is 3.

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Detailed Solution

MgCO3(s)84 g⟶ΔMgO(s)40 g+CO2(g) 84 g of MgCO3≡40 g of MgO∴ 20 g of MgCO3≡4084×20=9.52 g of MgO Actual yield =8 g of MgO∴ % purity =89.52×100=84%

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