0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is
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a
12
b
24
c
6
d
36
answer is A.
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Detailed Solution
1 mol of O2 = 4 eq.of O22400 mL of O2 = 4 eq. of O46.6 mL of O2 = 422400×46.6=0.00832 eqEquivalent of metal = Equivalent of OWeightEw=0.008320.1E=0.00832 ∴E=0.10.00832=12.0