Q.

0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is

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a

12

b

24

c

6

d

36

answer is A.

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Detailed Solution

1 mol of O2 = 4 eq.of O22400 mL of O2 = 4 eq. of O46.6 mL of O2 = 422400×46.6=0.00832 eqEquivalent of metal = Equivalent of OWeightEw=0.008320.1E=0.00832 ∴E=0.10.00832=12.0
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