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Q.

0.5 g of metal nitrate gave 0.43 g of metal carbonate. The equivalent weight of metal is ____.

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answer is 166.57.

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Detailed Solution

Let the equivalent weight of metal - E Ew of metal nitrate = Ew of M+Ew of NO3θ=E+62Equivalent weight of metal carbonate - Equivalent weight of Metal + Equivalent weight of CO32-=E+602=E+30 Ew of metal nitrate  Ew of metal carbonate = Weight of metal nitrate  Weight of metal carbonate E+62E+30=0.50.43∴E=166.57
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0.5 g of metal nitrate gave 0.43 g of metal carbonate. The equivalent weight of metal is ____.