1.020 g of metallic oxide contains 0.540 g of the metal. If the specific heat of the metal, M is 0.216 cal deg-1 g-1. The molecular formula of its oxide is

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

M2O3

M2O4

M2O

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Mass of oxygen in the oxide = (l .O2O- 0.540)= 0.480g Equivalent mass of the metal =0.5400.480×8=9.0According to Dulong and Petit's law, Approx. atomic mass =6.4 Sp. heat =6.40.216=29.63 Valency of the metal = At. mass Eq. mass =29.639.0=3 Hence, the formula of the oxide is M2O3.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET