1.0 g of a monobasic acid when completely acted upon Mg gave 1.301 g of anhydrous Mg salt. Equivalent weight ofacid is
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a
35.54
b
36.54
c
17.77
d
18.27
answer is B.
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Detailed Solution
Ew of acidEw of salt of Mg=Weight of acidWeight of saltMg + 2HCl (monobasic acid) → MgCl2+H2Let Ew of acid = Ew of H + Ew of acid radical∴Ew of salt of Mg = Ew of Mg + Ew of acid radical∴Ew acidEw of Mg salt=weight of acidWeight of Mg salt⇒Ew of H + Ew of acid radical (E)Ew of Mg + Ew of acid radical (E) =1.01.301⇒1+E12+E=1.01.301∴E=35.54∴Ew of acid = Ew of H + Ew of acid radical=1+35.54 = 36.54