Q.

58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point (bp) of the resulting solution.

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NaCl solution will show higher elevation of boiling point

glucose solution will show higher elevation of boiling point

both the solutions will show equal elevation of boiling point

the boiling point elevation will be shown by none of the solutions

answer is A.

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Detailed Solution

Elevation in boiling point, ∆Tb=i×Kb×mMolality of NaCl solution =nw×1000 =58.558.5wH2o×1000=1000wH2oMolality of C6H12O6solution =180180×1000wH2O=1000wH2OBoth solutions have same molality but values of i i.e. van't Hoff factor for NaCl and glucose are 2 and 1 respectively.Hence, NaCl will show higher elevation in boiling point.

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