20 g of napthoic acid C11H8O2. Dissolves in 50 g of benzene Kf=1.72 K kg mol−1 shows a depression in freezing point of 2K. The Van’t Hoff factor is
Molar mass = 12×11+8+32=132+40=172
ΔTf=i Kf m
2=i 1.7220100017250
2=i4
i=0.50