20 g of napthoic acid C11H8O2. Dissolves in 50 g of benzene Kf=1.72 K kg mol−1 shows a depression in freezing point of 2K. The Van’t Hoff factor is

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answer is 0000.50.

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Detailed Solution

Molar mass = 12×11+8+32=132+40=172ΔTf=i Kf m2=i 1.72201000172502=i4i=0.50

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