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a
7 g of CO
b
14 g of CO
c
28 g of CO
d
11 g of CO2
answer is A.
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Detailed Solution
Moles of O2= 8 /32 =0.25 molesNo. of molecules =No. of moles × NA. Thus, no. of moles is directly proportional to no. of molecules.Moles of 7 gm CO= 7/28 =0.25Moles of 14 gm CO= 14 /28 =0.5Moles of 22 gm CO2= 22 /44 =0.5Moles of 11 gm of CO2 =11/44 =0.25