0.30 g of an organic compound on combustion yields O.44 g CO2 and 0.18 g H2O. If V.D. of compound is 30, the molecular formula of compound is :

Molar mass =2×30=60gC%=1244×0.440.30×100=40%H%=218×0.180.30×100=6.66%O%=100−40+6.66=53.34%C:H:O =4012:6.661:53.3416=3.33:6.66:3.33=1: 2 : 1EF=CH2O;  EFW = 12 + 2 + 16 = 30n=MFWEFW=6030=2MF=EFn=CH2O2=C2H4O2