44g of a sample on complete combustion gives 88gmCO2 and 36gm of H2O.The molecular formula of the compound may be:

CO2=8844=2 mole of CO2=2 moleof CH2O=3618=2 mole of H2O=4 moleof HMass of C + Mass of H + Mass of O = 44⇒24+4+x=44;x=16∴ mole of O = 1 and molecular formula is C2H4O.