A 0.518 g sample of limestone is dissolved in HCl and then the calcium is precipitated as CaC2O4. After filtering and washing the precipitate, it requires 40.0 mL of 0.250 N KMnO4 solution acidified with H2SO4 to titrate it as. The percentage of CaO in the sample isMnO4- + H+ + C2O4-2 → Mn2+ +CO2 + 2H2O
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a
54.0%
b
27.1%
c
42%
d
84%
answer is A.
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Detailed Solution
M eq. of KMnO4 = M eq. of C2O4-2 = M eq. of CaCO340 x .25 = Meq of CaO10 × 10-32 = Mole of CaO % CaO = 5 ×10-3 × 56 × 100 .518 CaO = 54%