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Q.

0.15 g of a substance dissolved in 15 g of solvent boiled at a temperature higher by 0.216oC than that of the pure solvent. Calculate the molecular weight of the substance. Molal elevation constant for the solvent is 2.16oC.

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a

216

b

100

c

178

d

None of these

answer is B.

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Detailed Solution

Here it is given that w=0.15 g              ΔTb=0.216oCW=15 g                Kb=2.16oCm=?Substituting values in the expression, we have m=1000×Kb×wΔTb×Wm=1000×2.16×0.150.216×15=100
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