Q.

4 g of sulphur is burnt to form SO2, which is oxidised by Cl2 water. The solution is then treated with BaCl2 solution.The amount of BaSO4 precipitated is:

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a

0.24 mol

b

0.5 mol

c

1 mol

d

0.125 mol

answer is D.

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Detailed Solution

Moles of S = 432=18=0.125 molS+O2→ SO2SO2+Cl2→ 2Cl⊝+SO42-SO42-+BaCl2→BaSO4+2Cl⊝ Moles of S = Moles of SO2 = Moles of SO42-= Moles of BaSO4 = 0.125 mol
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4 g of sulphur is burnt to form SO2, which is oxidised by Cl2 water. The solution is then treated with BaCl2 solution.The amount of BaSO4 precipitated is: