4 g of sulphur is burnt to form SO2, which is oxidised by Cl2 water. The solution is then treated with BaCl2 solution.The amount of BaSO4 precipitated is:
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a
0.24 mol
b
0.5 mol
c
1 mol
d
0.125 mol
answer is D.
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Detailed Solution
Moles of S = 432=18=0.125 molS+O2→ SO2SO2+Cl2→ 2Cl⊝+SO42-SO42-+BaCl2→BaSO4+2Cl⊝ Moles of S = Moles of SO2 = Moles of SO42-= Moles of BaSO4 = 0.125 mol