ΔG∘ vs T plot in the Ellingham diagram slopes down for the reaction.
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a
Mg+12O2⟶MgO
b
2Ag+12O2⟶Ag2O
c
C+12O2⟶CO
d
CO+12O2⟶CO2
answer is C.
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Detailed Solution
In the case of carbon reacting with dioxygen.C+12O2⟶COtwo volumes of CO for every one volume of dioxygen used. Thus ∆S is positive and hence ∆G becomes increasingly negative as temperature increases. Consequently the line on Ellingham diagram slope downwards.