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Q.

A Galvanic cell comprises of two half cells, EMg2+/Mg0=−2.37V and  EAl3+/Al0=−1.66V Oxidation takes place at __________electrode and cell emf is ___________

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answer is 3.

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Detailed Solution

Magnesium electrode, 0.71VThe electrode with maximum negative potential or least positive potential will be the Anode, where Oxidation takes place. Ecell=Ecathode−Eanode=−1.66−(−2.37)=0.71V
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A Galvanic cell comprises of two half cells, EMg2+/Mg0=−2.37V and  EAl3+/Al0=−1.66V Oxidation takes place at __________electrode and cell emf is ___________