First slide

First law of thermo dynamics

Question

A gas abosorbs 400 J of heat and expands by 2 $\times$ 10^-3m³against a constant pressure of 10⁵Nm^-2. The change in internal energy is

Easy

Solution

$W_{irrev} = - P_{ext} ∆ V; W_{irrev} = - (10^{5} N m^{- 2}) (2 \times 10^{- 3} m^{3}) = - 200 J; Heat absorbed, q = + 400 J; ∆ E = + 400 J + (- 200 J); ∆ E = + 200 J;$

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