A gas absorbs 100 J of heat and is simultaneously compressed by a constant external pressure of 1.50 atmospheres from a volume of 8 L to 2 L. ∆E will be
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Detailed Solution
∆H=100 JWork done P∆V=1.5-6. Now, this work done is in litre atmospheres. To obtain the same in joules, multiply by 8.314 and divide by 0.0821∴ ∆H=∆E+ P∆V or, 100 =∆E+ 1.5-60.0821×8.314 or, ∆E = 1011.4 J