A gas absorbs 100 J of heat and is simultaneously compressed by a constant external pressure of 1.50 atmospheres from a volume of 8 L to 2 L. ∆E will be

ΔH=100J Work done PΔV=1.5(−6). Now, this work done is in liter atmospheres. To obtain the same in joules, multiply by 8.314 and divide by 0.0821.∴ΔH=ΔE+PΔV Or, 100=ΔE+1.5(−6)0.0821×8.314 Or, ΔE=1011.4J