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A gas mixture of 3 liters of propane C3H8and butane C4H10on combustion at 25°C produced 10 liters CO2.Find out volume of propane in liter in the mixture.

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Detailed Solution

C3H8+5O2→3CO2+4H2O(l)C4H10+132O2→4CO2+5H2O(l) Let 'a' litre of C3H8 and ' b ' litre of C4H10 be present in mixture. ∴a+b=3 . . .. (1)10=3 a+4 b . . . (2)Solving equations (1) and (2) b = 1 liter a = 2 liter

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A gas mixture of 3 liters of propane C3H8and butane C4H10on combustion at 25°C produced 10 liters CO2.Find out volume of propane in liter in the mixture.