First slide

Gaseous state

Question

A gas obeys the equation of state p(V - b) = RT where b is constant. The slope for an isochore will be

Moderate

A

negative
B

zero
C

$\frac{R}{(V - b)}$
D

$\frac{R}{p}$

Solution

$p (V - b) = RT p = \frac{RT}{(V - b)} (cornpare with Y = mx)$
A graph between p and T at constant volume (isochoric) is a straight line of slope = $\frac{R}{(V - b)}$

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