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Q.

A gas present in a cylinder fitted with a frictionless piston expands against a constant pressure of 1 atm from a volume of 2 liters to a volume of 6 liters. In doing so, it absorbs 800 J heat from surroundings. Determine increase in internal energy of process.

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answer is 394.95 JOULE..

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Detailed Solution

ΔV=(6−2)=4 liter ; P=1atmW=−1×4 liter atm =−1×4×1.9870.0821cal (since 0.0821 liter atm =1.987cal ) =−96.81cal=−96.81×4.184J (∴ 1cal=4.184J)=−405.05JNow from first law of thermodynamics,q=ΔU−W800=ΔU+405.05ΔU=394.95 joule.
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