A gas was found to have density 20 at 27° C and 1.0 bar pressure. If pressure remains constant, calculate the temperature at which its density would be 16.

Density, D1=20; T1=27+273=300K;T2=?density, D2=16. Since pressure is constant, it is Charle's law.We know that :V∝T. But T∝1D. So T∝1D or DT = constant.Hence D1T1=D2T2;T2=D1T1D2=20×300K16=375Kor T2=375−273=102∘C