A gaseous hypothetical chemical equation 2A⇌4B+C is carried out in a closed vessel. The concentration of C is found to increase by 5×10−3 mol L−1 in 10 second. The rate of appearance of C is

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5×10−4 mol L−1 sec−1

5×10−5 mol L−1 sec−1

6×10−5 mol L−1 sec−1

4×10−4 mol L−1 sec−1

answer is A.

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Detailed Solution

Increase in concentration of C=5×10−3 mol L−1Time = 10 sec Rate of appearance of C = 5×10-310 = 5×10-4 mole/lit sec

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