A gaseous mixture containing CO,$$CH4$$ and $$N2$$ gas has total volume of $$40ml$$. This mixture is exploded with excess of oxygen. On cooling the mixture, a contraction of $$30ml$$ is observed and when this mixture is exposed to aqueous KOH solution, a further contraction of $$30ml$$ is observed. Then the composition of the mixture is $$___$$?

Question

A gaseous mixture containing  CO,$$CH4$$ and $$N2$$ gas has total volume of $$40ml$$. This mixture is exploded with excess of oxygen. On cooling the mixture, a contraction of $$30ml$$ is observed and when this mixture is exposed to aqueous KOH solution, a further contraction of $$30ml$$ is observed.  Then the composition of the mixture is $$___$$?

Infinity Learn · Accepted Answer

Let volume of CO is “x” ml   volume of $$CH4is$$ “y” mlVolume of  $$N2$$ is “z” $$mlCO(g)+1/2O2(g)$$→$$CO2(g)x$$ ml                                   x $$mlCH4(g)+O2(g)$$→$$CO2(g)+2H2O(g)y$$ ml                            y ml         $$2y$$” $$mlN2$$ remains unreactedOn cooling $$H2O(g)$$ liquefied. So volume of reduction is $$30ml.2y$$ $$=$$  $$30$$ ;       y    $$=$$    $$15But$$ volume of $$CO2obtained$$  $$=$$   (x+y) mlThis is absorbed in KOH & Volume  reduction of $$30ml$$ is observed.$$x+y$$    $$=$$   $$30(x$$    $$=$$   $$30$$ – y   $$=$$    $$30$$ – $$15)$$  $$=$$    $$15and$$  $$x+y+z$$    $$=$$    $$40$$∴$$z=40-x-y=40-15-15=10Composition$$ of mixture  isVol. of  CO    $$=$$     $$15$$ ml Vol. of $$CH4=15ml$$

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