A gaseous mixture contains 8 grams of oxygen, 14 grams of Nitrogen, 9 grams of water vapour. Partial pressure of water vapour in the mixture is (Assume water vapour behaves like ideal gas)

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Detailed Solution

nN2=1428=12;nO2=832=14;nH2O=918=12XH2O=nH2OnN2+nO2+nH2O=1212+14+12=12×45=410

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