A gaseous mixture of propane and butane of volume 3litre on complete combustion produces 11.0 litre CO2 under standard conditions of temperature and pressure. The ratio of volume of butane to propane is:

Suppose, the volume of propane = V L∴C3H8(g)V+5 O25V(g)⟶33VCO2(g)+4H2O(l)C4H10(g)(3-v)+132O2(g)132(3−V)⟶4CO2(g)4(3-v)+5H2O(l)∵Total volume of CO2 produced = 11 L;∵ 3V + 4(3 -V) =11; ∴V=1∴ Volume of butane = (3-1) = 2 LThus, the ratio of volume of butane to Propane = 2 :1