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Gaseous N2O5 decomposes according to the following equation: N2O5(g)→2NO2(g)+12O2(g)The experimental rate law is −Δ[N2O5]/Δt=k[N2O5]. At a certain temperature the rate constant is k=5.0×10−4sec⁡−1. In how many seconds will the concentration of N2O5 decrease to one-tenth of its initial value?

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a

2.0×103s

b

4.6×103s

c

2.1×102s

d

1.4×103s

answer is B.

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Detailed Solution

t=2.3035×10−4log⁡A0A0/10 =4.6×103sec⁡.

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Gaseous N2O5 decomposes according to the following equation: N2O5(g)→2NO2(g)+12O2(g)The experimental rate law is −Δ[N2O5]/Δt=k[N2O5]. At a certain temperature the rate constant is k=5.0×10−4sec⁡−1. In how many seconds will the concentration of N2O5 decrease to one-tenth of its initial value?