Q.

For the gaseous phase reaction 2A+B⇌2C+D , initially there are 2 mole each of A & B. If 0.4 mol of D is present at equilibrium at a given T & P, incorrect relationship is

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a

PA

b

PA=PC & PB=PD

c

PC=2PD & PA=3PB4

d

PA>PD & PB>PC

answer is B.

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Detailed Solution

2A    +     B   ⇌   2C   +  D 2                 2              0        0      Initial (2-2x)    (2-x)        2x       x      EquilibriumBut D at Equilibrium = 0.4So x = 0.4A=2-2(0.4)=1.2 B=2-x=2-0.4=1.6 C=2(0.4)=0.8 D=0.4 PB>PA>PC>PC PC=2PD PA=3PB4
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