For the gaseous phase reaction 2A+B⇌2C+D , initially there are 2 mole each of A & B. If 0.4 mol of D is present at equilibrium at a given T & P, incorrect relationship is
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a
PA
b
PA=PC & PB=PD
c
PC=2PD & PA=3PB4
d
PA>PD & PB>PC
answer is B.
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Detailed Solution
2A + B ⇌ 2C + D 2 2 0 0 Initial (2-2x) (2-x) 2x x EquilibriumBut D at Equilibrium = 0.4So x = 0.4A=2-2(0.4)=1.2 B=2-x=2-0.4=1.6 C=2(0.4)=0.8 D=0.4 PB>PA>PC>PC PC=2PD PA=3PB4