For the gaseous phase reaction , initially there are 2 mole each of A&B. If 0.4 mol of D is present at equilibrium at a given T & P, incorrect relationship is
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a
PA< PB&PD
b
PA= PC&PB =PD
c
d
PA> PD&PB >PC
answer is B.
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Detailed Solution
According to stoichiometryi) 2 molesof A gives 1 mole of D ______ gives 0.4 moles of D moles of A reacted = 0.8ii) 1 mole of B gives 1 mole of D _____ gives 0.4 moles of Dmoles of B reacted = 0.4iii) when 2 moles of 'C' is formed then 1 mole of D is formed ________ is formed then 0.4 moles of D is formed moles of C formed = 0.8At equilibriumnA = 1.2nB = 1.6nC = 0.8nD = 0.4Pressure exerted by gas α number of molesPA < PB .... correctPD < PC .... correctPA < PC .... correctPB < PC .... correctPC < PD .... correctPA < .... correctPA < PB .... correctPA < PB .... correct