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Q.

For a gaseous phase reactionWhen equilibrium is set up, K = 0.33Energy involved (in kJ) is

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a

0.595

b

1.785

c

0.7854

d

1.5875

answer is A.

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Detailed Solution

Cis ⇌ Trans Initial 1 0At equilib. (1 - x) xK=x1−x=0.333=13∴ x = 0.25Thus, there is 25% conversion into trans-form.∴ΔrH∘( net )=2.38×0.25=0.595kJ
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For a gaseous phase reactionWhen equilibrium is set up, K = 0.33Energy involved (in kJ) is