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Q.

For a gaseous reaction. A+3B⇌2C; ΔH0=−90KJ;  ΔS0=−200JK−1at 400K for the reaction 12A+32B⇌Cat 400K ΔG0  is

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answer is 5.

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Detailed Solution

ΔG0=ΔH0−TΔS0 =-90-400(-0.2)=-90+80=-10KJ ∴12A+32B⇌CΔG0=-5KJ
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