A gaseous system undergoes a change of state from (A) to (B) by any of the given path. Path I or path II as shown in figureAs per path I,Δq=−400cal and ΔW=14cal As per path II, Δq=−48 cal. Therefore work done, ΔW in path (II) is
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a
- 338 cal
b
- 366 cal
c
- 434 cal
d
- 462 cal
answer is A.
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Detailed Solution
For path I ΔEI=Δq+ΔW=−400+14=−386cals For path II, ΔEII=ΔEI=−48+ΔW∴ ΔW=−386+48=−338cal