A Geigger Muller counter is used to study the radioactive process. In the absence of radioactive substance A, it counts 3 disintegration per second (dps).At the start in the presence of A, it records 23 dpr; and after 10 min 13 dps,i. What does it count after 20 min?ii. What is the half life of A?
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a
8 dps, 10 min
b
5 dps, 10 min
c
5 dps, 20 min
d
5 dps, 5 min
answer is A.
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Detailed Solution
In the absence of A, 3 dps is zero error, henceInitial count = 23 - 3 = 20 dpsAfter 10 min = 13 - 3 = 10 dpsAfter 20 min = 5 dps (recorded = 5 + 3 = 8 dps)(50% fall in 10 min, T50 =10 min)